Q.(+50)
f(x) = (100-x³)+(38²-x)
f(-2) + f(3) = ..
![]()
f(x) = (100-x³)+(38²-x)
f(-2) + f(3) = ..
f(x) = (100-x³)+(38²-x)
[tex]~[/tex]
f(-2) = (100-(-2)³)+(38²-(-2))
f(-2) = (100-(8))+(1.444+ 2)
f(-2) = 92 + 1.446
f(-2) = 1.538
[tex]~[/tex]
f(3) = (100-(3)³)+(38²-(3))
f(3) = (100-27)+(1.444 - 3)
f(3) = 73 + 1.441
f(3) = 1.514
[tex]~[/tex]
f(-2) + f(3)
= 1.538 + 1.514
= 3.052
Penyelesaian :
f(x) = (100 × X^3) + (38^2 - X)
f(-2) + f(3) = ...?
___________________
f(-2) = (100 - (-2^3) + (38^2 - X)
f(-2) = 100 - (-2 × -2 × -2) + (38 × 38) - (-2)
f(-2) = 100 - (8) + 1.444 - (-2)
f(-2) = 92 + 1.444 - (-2)
f(-2) = 1.536 - (-2)
f(-2) = 1.538
________________________
f(3) = (100 - X^3) + (38^2 - X)
f(3) = (100 - (3 × 3 × 3) + (38 × 38) - 3
f(3) = (100 - 27) + (1.444 - 3)
f(3) = 73 + 1.441
f(3) = 1.514
= f(-2) + f(3)
= 1.538 + 1.514
= 3.052
~Muichiro~
[answer.2.content]
